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Q.

A transistor is connected in common emitter configuration. The collector – emitter voltage is 8 volt and a load resistance of 800 Ω is connected in the collector circuit. The voltage drop across the load resistance is 0.5 volt. If the current gain be 0.96, What is the base current?

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a

5μA

b

8μA

c

9.6μA

d

None

answer is D.

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Detailed Solution

IC=0.5800  A=58  mA       β=α1−α=24 Now         ICIB=β   ⇒   IB=58 × 124 mA=26  μA
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