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Q.

A transistor is connected in common emitter configuration. The collector supply is 8V and the voltage drop across a resistor of 800Ω in the collector circuit is 0.5 V. If the current gain factor α is 0.96, the base current will be

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a

24 μA

b

26 μA

c

32 μA

d

20 μA

answer is B.

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Detailed Solution

icRL = 0.5ic = 0.5800 = 11600α = 0.96β = α1−α = 0.960.04 = 24β = IcIB24=IcIBIB = Ic24=11600×24 ≃ 26μA

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