A transistor connected in common - emitter mode configuration is used as an amplifier. If RL=5kΩ and input resistance Ri=2kΩ and current gain is 50. Its power gain is
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
1250
b
2500
c
6250
d
12,500
answer is C.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
Power gain=A×β =β×RLRi×β P=β2×RLRi =50×50×5002000 =6250