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For a transistor, the current amplification factor is 0.8. The transistor is connected in common emitter configuration . The change in the collector current when the base current changes by 6 rnA is

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6 rnA

4.8 rnA

24 rnA

8 rnA

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detailed solution

Correct option is C

α=0.8⇒β=0.81-0.8=4 Also β=∆ic∆ib⇒∆ic=β×∆ib=4×6=24 mA

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