First slide

Transistor

Question

For a transistor, the current amplification factor is 0.8. The transistor is connected in common emitter configuration . The change in the collector current when the base current changes by 6 rnA is

Moderate

A

6 rnA
B

4.8 rnA
C

24 rnA
D

8 rnA

Solution

$α = 0.8 \Rightarrow β = \frac{0.8}{1 - 0.8} = 4 Also β = \frac{∆ i_{c}}{∆ i_{b}} \Rightarrow ∆ i_{c} = β \times ∆ i_{b} = 4 \times 6 = 24 mA$

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