First slide

Transistors

Question

In a transistor if $\frac{I_{C}}{I_{E}} = α$ and $\frac{I_{C}}{I_{B}} = β$ , if $α$ varies between $\frac{20}{21}$ and $\frac{100}{101}$ , then the value $β$ of lies between

Moderate

A

1 – 10
B

0.95 – 0.99
C

20 – 100
D

200 – 300

Solution

$β = \frac{α}{1 - α} β = \frac{α}{1 - α} = \frac{\frac{20}{21}}{1 - \frac{20}{21}} = \frac{\frac{100}{101}}{1 - \frac{100}{101}} = \frac{\frac{20}{21}}{\frac{1}{21}} = \frac{\frac{100}{101}}{\frac{1}{101}} β = 20 β = 100 ∴ β l i e s b e t w e e n 20 - 100$

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