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Questions  

A transistor is used as an amplifier. A resistance of 0.5 kΩ is connected as load resistance in the collector circuit. When base current changes by 80 μA, the potential drop in the load resistance changes by 4 volt. The current amplification factor of transistor is

a
40
b
50
c
80
d
100

detailed solution

Correct option is D

ΔIc=ΔVcRL=40.5×103=8×10−3 Aβ=ΔIcΔIb=8×10−380×10−6=100

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