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Q.

A transistor is used as an amplifier. A resistance of 0.5 kΩ is connected as load resistance in the collector circuit. When base current changes by 80 μA, the potential drop in the load resistance changes by 4 volt. The current amplification factor of transistor is

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a

40

b

50

c

80

d

100

answer is D.

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Detailed Solution

ΔIc=ΔVcRL=40.5×103=8×10−3 Aβ=ΔIcΔIb=8×10−380×10−6=100
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