First slide

Transistor

Question

A transistor is used as an amplifier. A resistance of $0 .5 k Ω$ is connected as load resistance in the collector circuit. When base current changes by $80 μ A$ , the potential drop in the load resistance changes by 4 volt. The current amplification factor of transistor is

Moderate

A

40
B

50
C

80
D

100

Solution

$\begin{array}{l} {ΔI}_{c} = \frac{{ΔV}_{c}}{R_{L}} = \frac{4}{0 .5 \times 10^{3}} = 8 \times 10^{- 3} A \\ β = \frac{{ΔI}_{c}}{{ΔI}_{b}} = \frac{8 \times 10^{- 3}}{80 \times 10^{- 6}} = 100 \end{array}$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App