First slide

Law of equipartition of energy

Question

The translatory kinetic energy of a gas per g is

Moderate

A

$\frac{3}{2} \frac{RT}{N}$
B

$\frac{3}{2} \frac{RT}{M}$
C

$\frac{3}{2} RT$
D

$\frac{3}{2} NKT$

Solution

Kinetic energy for $1 g \Rightarrow E_{Tran} = \frac{3}{2} rT = \frac{3}{2} \frac{RT}{M}$

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