A transparent solid cylindrical rod has a refractive index of 23. It is surrounded by air. A light ray is incident at the midpoint of one end of the rod as shown in the figure.The incident angle θ for which the light ray grazes along the wall of the rod is
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a
sin-132
b
sin-123
c
sin-113
d
sin-112
answer is C.
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Detailed Solution
c = 90–r(1) sin90= μsinc = μcos r⇒cos r=1μ=32, r=30o(1) sinθ = μsin rsinθ=23 x 12=13 ; sinθ=13 θ=sin-113