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The transverse displacement of a string fixed at both ends is given by −y, x are in meter y=0.06sin2πx3cos120πt and t in sec the length of string is 1.5 m and its mass is 3×10−3kg . Find amplitude at point x=0.5m.

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a

0.02 m

b

0.052 m

c

0.4 m

d

0.6 m

answer is B.

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Detailed Solution

Displacement is maximum when cos120πt=1 Hence the amplitude =0.06sin2πx3 At x=0.5 m A=0.06sin2π3×0.5 =0.052 m

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The transverse displacement of a string fixed at both ends is given by −y, x are in meter y=0.06sin2πx3cos120πt and t in sec the length of string is 1.5 m and its mass is 3×10−3kg . Find amplitude at point x=0.5m.