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Questions  

A transverse sinusoidal wave of amplitude a, wavelength λ and frequency f is travelling on stretched string. The maximum speed of any point on the string is v/10, where v is the speed of propagation of the wave. If a=103m and v = 10 m/s, then λ and f are given by

a
λ=2π×10−2m
b
λ=10−3m
c
f=1032πHz
d
f=104 Hz

detailed solution

Correct option is A

Aω=V/10aω=v/10     … (i)v=ω/k     … (ii)from (i) and (ii)k=110×10−3 ⇒k=100⇒λ=2π×10−2mω=vk=  10×100⇒2πf=103⇒   f=1032πHz

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