A transverse wave is described by the equation Y = Yo sin 2π(ft-xλ). The maximum particle velocity is four times the wave velocity if
λ = πY04
λ = πY02
λ = πY0
λ = 2πY0
Comparing the given equation with y = asin(ωt-kx).We get a = Yo, ω = 2πf, k = 2πλ. Hence maximum particle velocity (vrms)particle = aω = Y0×2πf and wave velocity (v)wave = ωk = 2πf2πλ = fλ∵ (vmax)particle = 4vwave ⇒ Y0×2πf = 4fλ
⇒ λ = πY02