A transverse wave is described by the equation y = yo sin 2πft - xλ .The maximum particle velocity is equal to four times the wave velocity if :
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a
λ = πyo4
b
λ = πyo2
c
λ = πyo
d
λ = 2πyo
answer is B.
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Detailed Solution
Wave velocity v = coefficient of tcoefficient of x = 2πf2π/λ = λf Maximum particle velocity vpm = ωA = 2πfyo Given, vpm = 4v or 2πfyo = 4λ f ∴ λ = πyo2 ∴ correct option is (B)