A transverse wave is propagating along +x direction. At t = 2 sec, the particle at x = 4 m is at y = 2 mm. With the passage of time its y coordinate increases and reaches to a maximum of 4 mm. The wave equation is(using at and k with their usual meanings)

• A

  $\mathrm{y} = 4\sin \left[\mathrm{\omega }\right(\mathrm{t}+2)+\mathrm{k}(\mathrm{x}-2)+\frac{\mathrm{\pi }}{6}]$

• B

  $\mathrm{y} = 4 \sin \left[\mathrm{\omega }\right(\mathrm{t}+2)+\mathrm{k}(\mathrm{x})+\frac{\mathrm{\pi }}{6}]$

• C

  $\mathrm{y} = 4 \sin \left[\mathrm{\omega }\right(\mathrm{t}-2)-\mathrm{k}(\mathrm{x}-4)+\frac{5\mathrm{\pi }}{6}]$

• D

  $\mathrm{y} = 4 \sin \left[\mathrm{\omega }\right(\mathrm{t}-2)-\mathrm{k}(\mathrm{x}-4)+\frac{\mathrm{\pi }}{6}]$