A transverse wave propagations on a stretched string of linear density is 3×10−4 Kg/m . Represented by equation y=0.2Sin(1.5 x+60 t) where 'x' is in meters and 't' is in seconds. The tension in string
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a
0.24
b
0.48
c
1.20
d
1.80
answer is B.
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Detailed Solution
Given , Linear density μ=3×10−4 kg/m Progressive wave y=0.2sin(1.5x+60t) Tension T=? Progressive wave y=Asin(kx+ωt) A=0.2, k=1.5, ω=60 Wave velocity=ωk=601.5=40 m/s v=Tμ 40=T3×10−4 1600=T3×10−4 ∴ T=0.48 N