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Q.

A transverse wave propagations on a stretched string of linear density is 3×10−4 Kg/m . Represented by equation y=0.2Sin(1.5 x+60 t) where 'x' is in meters and  't' is in seconds.  The tension in string

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a

0.24

b

0.48

c

1.20

d

1.80

answer is B.

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Detailed Solution

Given , Linear density μ=3×10−4 kg/m Progressive wave y=0.2sin(1.5x+60t) Tension T=? Progressive wave y=Asin(kx+ωt) A=0.2, k=1.5, ω=60 Wave velocity=ωk=601.5=40 m/s v=Tμ 40=T3×10−4 1600=T3×10−4  ∴ T=0.48 N
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