A transverse wave is represented by the equationy=y0sin2πλ(vt−x)For what value of λ, the maximum particle velocity equal to two times the wave velocity
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a
λ=2πy0
b
λ=πy0/3
c
λ=πy0/2
d
λ=πy0
answer is D.
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Detailed Solution
On comparing the given equation with standard equation y=asin2πλ(vt−x). It is clear that wave speed (v)wave=v and maximum particle velocity (vmax)particle=aω=y0× co-efficient of t=y0×2πvλ ∵ (vmax)particle=2(ω)wave⇒a×2πvλ=2v⇒λ=πy0