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Q.

A transverse wave on a stretched string is represented by the equation y=0.4  sin60t−20x, where x is in metre and t is in second. It linear mass density of the wire is 16 × 10−3 kg/m, the tension in the string is

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a

2.21 N

b

1.106 N

c

0.238 N

d

0.144 N

answer is D.

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Detailed Solution

(4)y=0.4  sin60t−20x∴  V=Velocity  of propagation  =  ωk=6020 m/s⇒   v=3  m/sNow   Tμ=V     ⇒   T=μV2  16 × 10−3 ×  32N⇒    Tclosed= 0.144  N
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