A transverse wave on a stretched string is represented by the equation y=0.4 sin60t−20x, where x is in metre and t is in second. It linear mass density of the wire is 16 × 10−3 kg/m, the tension in the string is

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2.21 N

1.106 N

0.238 N

0.144 N

answer is D.

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Detailed Solution

(4)y=0.4 sin60t−20x∴ V=Velocity of propagation = ωk=6020 m/s⇒ v=3 m/sNow Tμ=V ⇒ T=μV2 16 × 10−3 × 32N⇒ Tclosed= 0.144 N

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