A transverse wave travels on a taut steel wire with velocity of V when tension in it is 2.06×104N. When the tension is changed to T , the velocity changed to V/4 . The value of T is closed to
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a
10.2×102N
b
1.2875×103N
c
2.50×104N
d
1×104N
answer is B.
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Detailed Solution
V = Tμ ∴V ∝T ⇒V1V2=T1T2 ⇒VV4=TT1 ⇒16=TT1 ⇒T1=T16=2.06×10416=0.12875×104==1.2875×10+3N