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A travelling wave y = A sin(kx-ωt+θ) passes from a heavier string to a lighter string. The reflected wave has amplitude 0.5 A. The junction of the strings is at x = 0. The equation of the reflected wave is:

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a

y' = 0.5Asin(kx+ωt+θ)

b

y' = -0.5Asin(kx+ωt+θ)

c

y' = -0.5Asin(ωt-kx-θ)

d

y' = -0.5Asin(kx+ωt-θ)

answer is D.

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Detailed Solution

As wave has been reflected from a rarer medium, therefore there is no change in phase. Hence equation for the opposite direction can be written asy = 0.5Asin(-kx-ωt+θ) = -0.5Asin(kx+ωt-θ)

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A travelling wave y = A sin(kx-ωt+θ) passes from a heavier string to a lighter string. The reflected wave has amplitude 0.5 A. The junction of the strings is at x = 0. The equation of the reflected wave is: