A triangular plate is shown. A force F→=4i^−3j^  is applied at point P. The torque at point P with respect to point ‘O’ and ‘Q’ are:

Torque of force  F→=4i^−3j^ w.r.t  O τO→=rOP→×F→=10cos600 i^+10sin600 j^×4i^−3j^⇒τO→=5i^+53j^×4i^−3j^=i^                 j^          k^ 5      53       04        −3         0 ⇒τO→=k^−15−203       Torque of force  F→=4i^−3j^ w.r.t  Q  τ→Q=r→ PQ×F→ r→PQ =r→ P−r→ Q=(5i^+53j^)−10i^=(−5i^+53j^)τ→ Q=(−5i^+53j^)×(4i^−3j^)=i^j^k^−55304−30 =(15−203)k^          So the answer for given question is −15−203, 15−203