First slide
Numericals based on work energy theorem
Question

A trolley of mass m is connected to two identical springs, each of force constant k, as shown in fig. The trolly is displaced from its equilibrium position by a distance x and released. The trolly executes simple harmonic motion of period T. After some time it comes to rest due to friction. The total energy dissipated as heat is (assume the damping force to be weak)

Easy
Solution

Two springs are connected in parallel equivalent spring constant is – 2K.
Total energy  122Kx2=kx2
The final energy of the system = 0 
Hence the total energy dissipated is = kx2
 

Get Instant Solutions
When in doubt download our app. Now available Google Play Store- Doubts App
Download Now
Doubts App