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Q.

A trolley T of mass 5 kg on a horizontal smooth surface is pulled by a load of 2 kg through a uniform rope ABC of length 2 m and mass 1 kg. As the load falls from BC = 0 to BC = 2 m, its acceleration (in ms-2) changes from

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a

206 to 306

b

208 to 308

c

205 to 306

d

None of these

answer is A.

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Detailed Solution

Initial force =2g=20N Initial acceleration = Force  Mass =205+1=206ms−2 Final force =( Load + Mass of thread )×g                    =(2+1)×10=30N Therefore, final acceleration =306ms−2
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