A trolley T of mass $$5$$ kg on a horizontal smooth surface is pulled by a load of $$2$$ kg through a uniform rope ABC of length $$2$$ m and mass $$1$$ kg. As the load falls from BC $$=$$ $$0$$ to BC $$=$$ $$2$$ m, its acceleration (in$$ $$ms-2) changes from

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Infinity Learn · Accepted Answer

Initial force $$=2g=20N$$ Initial acceleration $$=$$ Force  Mass $$=205+1=206ms$$−$$2$$ Final force $$=($$ Load $$+$$ Mass of thread $$)$$×g                    $$=(2+1)$$×$$10=30N$$ Therefore, final acceleration $$=306ms$$−$$2$$

A trolley T of mass 5 kg on a horizontal smooth surface is pulled by a load of 2 kg through a uniform rope ABC of length 2 m and mass 1 kg. As the load falls from BC = 0 to BC = 2 m, its acceleration (in ms^-2) changes from

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A trolley T of mass 5 kg on a horizontal smooth surface is pulled by a load of 2 kg through a uniform rope ABC of length 2 m and mass 1 kg. As the load falls from BC = 0 to BC = 2 m, its acceleration (in ms-2) changes from

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A trolley T of mass 5 kg on a horizontal smooth surface is pulled by a load of 2 kg through a uniform rope ABC of length 2 m and mass 1 kg. As the load falls from BC = 0 to BC = 2 m, its acceleration (in ms^-2) changes from