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Q.

A trolley T of mass 5 kg on a horizontal smooth surface is pulled by a load of 2 kg through a uniform rope ABC of length 2 m and mass 1 kg. As the load falls from BC = 0 to BC = 2 m, its acceleration (in ms-2) changes from

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a

206to306

b

208to308

c

205to306

d

None of these

answer is A.

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Detailed Solution

Initial force = 2 g = 20 N Initial acceleration =  ForceMass=205+1=206ms−2 Final force = (Load + Mass of thread) × g   = (2 + 1) × 10 = 30 N Therefore, final acceleration 306ms−2
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