A truck of mass 30,000 kg moves up an inclined plane of slope 1 in 100 at a speed of 30 kmph. The power (kW)of the truck is (given  $\mathrm{g}=10{\mathrm{ms}}^{-2})$

As truck is moving on an incline plane therefore only component of weight  $\left(\mathrm{mgsin\theta }\right)$ will oppose the upward motion 
Power = force × velocity =  $\mathrm{mg} \mathrm{sin\theta }\times \mathrm{v}$
$=30000\times 10\times \left(\frac{1}{100}\right)\times \frac{30\times 5}{18}=25\text{\hspace{0.17em}k}W$