A truck is moving at a speed of 72 kmh-1 on a straight road. The driver can produce deceleration of 2 ms-2 by applying brakes. The stopping distance of truck is 13x m, if the reaction time of the driver is 0.2 s. The value of x is _________.

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answer is 8.

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Detailed Solution

∵ v2=u2+2as⇒02=72×5182−2×2s0∴ s0=4004=100m Thus, stopping distance =72×518×0.2+s0=4+100=104=13x∴ x=10413=8

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