First slide

Earth's Magnetism

Question

The true value of dip at a place is 45^o. If the vertical plane carrying the needle is turned through 60^o from the magnetic meridian, the apparent dip is

Moderate

A

tan^–1 (1/2)
B

tan^–1 (2)
C

tan^–1 (3)
D

tan^–1 ( $\sqrt{3}$ )

Solution

$\begin{array}{rcl} \tan δ_{1} & = & \frac{\tan δ_{2}}{\cos θ} = \frac{\tan 45^{0}}{\cos 60^{0}} = 2; \\ δ_{1} & = & \tan^{- 1} (2) \end{array}$

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