First slide

Standing waves

Question

A tube, closed at one end and containing air, produces, when excited, the fundamental note of frequency 512 Hz. If the tube is opened at both ends the fundamental frequency that can be excited is (in Hz):

Moderate

A

1024
B

512
C

256
D

128

Solution

$\begin{array}{l} ∴ f_{o} = \frac{v}{4 l} = 512 Hz \\ f_{o} = \frac{v}{2 l} = 2 f_{o} = 1024 Hz \end{array}$
$∴$ correct option is (A).

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