A tube 1 cm2 in cross-section is attached to the top of a vessel 1 cm high and of cross-section 100 cm2. Water is poured into the system filling it to a depth of 100 cm above the bottom of the vessel as shown in Fig. Take g = 10 ms-2. Now
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a
The force exerted by the water against the bottom of the vessel is 100 N.
b
The weight of water in the system is 1.99 N
c
Both (a) and (b) are correct
d
Neither (a) nor (b) is correc
answer is C.
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Detailed Solution
P =hdg= 100 cm × 1 g cm-3 × 1000 cm s-2 = 105 dyne cm-2F = 105×100 dyne = 100 NAgain, V = 199 cm3Weight = 199 × 1×1000 dyne = 1.99 N
A tube 1 cm2 in cross-section is attached to the top of a vessel 1 cm high and of cross-section 100 cm2. Water is poured into the system filling it to a depth of 100 cm above the bottom of the vessel as shown in Fig. Take g = 10 ms-2. Now