First slide

Fluid statics

Question

A tube 1 ${cm}^{2}$ in cross-section is attached to the top of a vessel 1 cm high and of cross-section 100 ${cm}^{2}$ . Water is poured into the system filling it to a depth of 100 cm above the bottom of the vessel as shown in Fig. Take g = 10 ${ms}^{- 2}$ . Now

Moderate

A

The force exerted by the water against the bottom of the vessel is 100 N.
B

The weight of water in the system is 1.99 N
C

Both (a) and (b) are correct
D

Neither (a) nor (b) is correc

Solution

$P = hdg = 100 cm \times 1 g {cm}^{- 3} \times 1000 cm s^{- 2} = 10^{5} dyne {cm}^{- 2}$
F = $10^{5} \times 100 dyne = 100 N$
Again, V = 199 ${cm}^{3}$
Weight = 199 $\times 1 \times 1000 dyne = 1.99 N$

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