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Q.

The tuned circuit of the oscillator in a simple AM transmitter employs 40μH coil and 12 nano-farad (nF) capacitor. If the oscillator output is modulated by audio frequency of  5 kHz, which of the following frequencies doesn’t appear in the output AM?

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a

fLSB = 225 kHz

b

fUSB = 235 kHz

c

fc = 230 kHz

d

fc = 235 kHz

answer is D.

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Detailed Solution

Given : L=40×10−6H ,  C=12×10−9F   ,   fm=5 kHz   Carrier frequency,  fc=12πLC ⇒fc=12×3.14480×10−15 ⇒fc=16.2848×10−14  ⇒fc=1076.28×6.9=1000043.332×103  ≃  230 kHz  fUSB=fm+fc=230+5=235KHz  fLSB=fm−fc=230−5=225KHz
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