Q.

The tuned circuit of an oscillator in a simple AM transmitter employs a 250 micro henry  Coil and 1 nf condenser. If the oscillator output is modulated by audio frequency upto 10 KHz, the frequency range occupied by the side bands in KHz is

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a

210 to 230

b

258 to 278

c

308 to 328

d

118 to 128

answer is C.

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Detailed Solution

Given : L=250×10−6H   ,   C=1×10−9F    and fm=10KHz=10×103Hz  Carrier Wave frequency, fc=12πLC=12π250×10−6×10−9 = =106×722=0.318×106 ⇒fc=318×103Hz = 318 KHz  Hence,  Lower side band  =fc−fm =318-10=308 KHz  Upper side band  =fc+fm =318+10=328 KHz
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The tuned circuit of an oscillator in a simple AM transmitter employs a 250 micro henry  Coil and 1 nf condenser. If the oscillator output is modulated by audio frequency upto 10 KHz, the frequency range occupied by the side bands in KHz is