The tuned circuit of an oscillator in a simple AM transmitter employs a $$250$$ micro henry Coil and $$1$$ nf condenser. If the oscillator output is modulated by audio frequency upto $$10$$ KHz, the frequency range occupied by the side bands in KHz is

Question

The tuned circuit of an oscillator in a simple AM transmitter employs a $$250$$ micro henry  Coil and $$1$$ nf condenser. If the oscillator output is modulated by audio frequency upto $$10$$ KHz, the frequency range occupied by the side bands in KHz is

Infinity Learn · Accepted Answer

Given : $$L=250$$×$$10$$−$$6H$$   ,   $$C=1$$×$$10$$−$$9F$$    and $$fm=10KHz=10$$×$$103Hz$$  Carrier Wave frequency, $$fc=12$$$$π$$$$LC=12$$$$π$$$$250$$×$$10$$−$$6$$×$$10$$−$$9$$ $$=$$ $$=106$$×$$722=0.318$$×$$106$$ ⇒$$fc=318$$×$$103Hz$$ $$=$$ $$318$$ KHz  Hence,  Lower side band  $$=fc$$−fm $$=318-10=308$$ KHz  Upper side band  $$=fc+fm$$ $$=318+10=328$$ KHz

The tuned circuit of an oscillator in a simple AM transmitter employs a 250 micro henry Coil and 1 nf condenser. If the oscillator output is modulated by audio frequency upto 10 KHz, the frequency range occupied by the side bands in KHz is

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