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Q.

The tuned cut of the oscillator in a simple AM transmitter employs a 40μH  coil and 12 nano farad capacitor. If the oscillator o/p is modulated by audio frequency of 5 kHz, which of the following frequencies doesn’t appear in the o/p AM?

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a

f USB=225 kHz

b

f USB=235 kHz

c

fc=230 kHz

d

fL=225 kHz

answer is A.

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Detailed Solution

fc=12πLC=12π 40 x 10−6x12x10−9 =230 KHz fm= 5 kHz  fUSB=fc+fm=230+5=235 kHz  fLSB=fc-fm=230-5=225 kHz
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