Download the app

Questions  

The tungsten filament of an electric lamp has a surface area A and a power rating P. If the emissivity of the filament is e and σ is Stefan's constant, the steady temperature of the filament will be 

a
P/(Aeσ)
b
[P/(Aeσ)]2
c
[P/(Aeσ)]1/2
d
[P/(Aeσ)]1/4

detailed solution

Correct option is D

We know that the energy radiated per second per unit area at temp. T is given by =σeT4The power radiated from the filament of area A is given by P=σeT4×A∴ T=PAeσ1/4

Talk to our academic expert!

+91

Are you a Sri Chaitanya student?


Similar Questions

For a black body at temperature 727°C, its radiating power is 60W and temperature of surrounding is 227° C. If temperature of black body is changed to 1227°C, then its
radiating power will be :


phone icon
whats app icon