A tuning fork arrangement (pair) produces 4 beats/sec with one fork of frequency 288 cps. A little wax is placed on the unknown fork and it then produces 2 beats/sec. The frequency of the unknown fork is
nA = Known frequency = 288 cps, nB = ?
x = 4 bps, which is decreasing (from 4 to 2) after loading i.e. x
Unknown fork is loaded so nB
Hence nA – nB = x Wrong
nB – nA = x Correct
nB = nA + x = 288 + 4 = 292 Hz.