A tuning fork arrangement (pair) produces $$4$$ $$beats/$$$$sec$$ with one fork of frequency $$288$$ cps. A little wax is placed on the unknown fork and it then produces $$2$$ $$beats/$$$$sec$$. The frequency of the unknown fork is

Question

Infinity Learn · Accepted Answer

nA $$=$$ Known frequency $$=$$ $$288$$ cps, nB $$=$$ ?x $$=$$ $$4$$ bps, which is decreasing (from$$ $$4$$ to $$2) after loading i.e. x↓Unknown fork is loaded so nB↓Hence nA – nB↓ $$=$$ x↓       →        Wrong           nB↓ – nA↓ $$=$$ x↓      →       Correct⇒ nB $$=$$ nA $$+$$ x $$=$$ $$288$$ $$+$$ $$4$$ $$=$$ $$292$$ Hz.

A tuning fork arrangement (pair) produces 4 beats/sec with one fork of frequency 288 cps. A little wax is placed on the unknown fork and it then produces 2 beats/sec. The frequency of the unknown fork is

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