Tuning fork F1 has a frequency of 256 Hz and it is observed to produce 6 beats/second with another tuning fork F2. When F2 is loaded with wax, it still produces 6 beats/second with F1. The frequency of F2 before loading was
nA = Known frequency = 256 Hz, nB = ?
x = 6 bps, which remains the same after loading.
Unknown tuning fork F2 is loaded so nB
Hence nA – nB = x ... (i) Wrong
nB – nA = x ... (ii) Correct
nB = nA + x = 256 + 6 = 262 Hz.