Tuning fork F1 has a frequency of 256 Hz and it is observed to produce 6 beats/second with another tuning fork F2. When F2 is loaded with wax, it still produces 6 beats/second with F1. The frequency of F2 before loading was
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a
253 Hz
b
262 Hz
c
250 Hz
d
259 Hz
answer is B.
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Detailed Solution
nA = Known frequency = 256 Hz, nB = ?x = 6 bps, which remains the same after loading.Unknown tuning fork F2 is loaded so nB↓Hence nA – nB↓ = x ... (i) → Wrong nB↓ – nA = x ... (ii) → Correct⇒ nB = nA + x = 256 + 6 = 262 Hz.