First slide

Speed of wave

Question

A tuning fork of frequency of 500 c/s is sounded on a resonance tube. The first and second resonance are obtained at 17 cm and 52 cm. The velocity of sound in m/sec is

Moderate

A

170
B

350
C

520
D

850

Solution

$For first resonance, l_{1} = Î» / 4 for second resonance l_{2} = \frac{3 Î»}{4} â´ l_{2} â l_{1} = \frac{Î»}{2} or Î» = 2 (l_{2} â l_{1}) or Î» = 2 (52 â 17) = 70 cm V = nÎ» = 500 Ã 70 = 3500 cm / \sec = 350 m / \sec$

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