Q.
Tuning fork A of frequency 258 Hz gives 8 beats with a tuning fork B. When prongs of B are cut and again A and B are sounded together , the number of beats heard remains same. The frequency of B in Hz is
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a
250
b
264
c
242
d
258
answer is A.
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Detailed Solution
When prongs of B are cut, its natural frequency increases. fB'−fA=fA−fB=8∴ fB=fA−8=250 Hz
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