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Q.

Tuning fork  A of frequency 258 Hz gives 8 beats with a tuning fork B. When prongs of B are cut and again A and B are sounded together , the number of beats heard remains same. The frequency of B in Hz is

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a

250

b

264

c

242

d

258

answer is A.

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Detailed Solution

When prongs of B are cut, its natural frequency increases. fB'−fA=fA−fB=8∴ fB=fA−8=250 Hz
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