First slide

Beats

Question

Tuning fork A of frequency 258 Hz gives 8 beats with a tuning fork B. When prongs of B are cut and again A and B are sounded together , the number of beats heard remains same. The frequency of B in Hz is

Moderate

A

250
B

264
C

242
D

258

Solution

When prongs of B are cut, its natural frequency increases.
$\begin{array}{l} {f_{B}}^{'} - f_{A} = f_{A} - f_{B} = 8 \\ ∴ f_{B} = f_{A} - 8 = 250 Hz \end{array}$

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