A tuning fork of frequency $$480$$ Hz produces $$10$$ beats per second when sounded with a vibrating sonometer string. What must have been the frequency of the string if a slight increase in tension produces lesser beats per second than before

Question

Infinity Learn · Accepted Answer

If suppose nS $$=$$ frequency of string $$=12lTmnf$$ $$=$$ Frequency of tuning fork $$=$$ $$480$$ Hz x $$=$$ Beats heard per second $$=$$ $$10as$$ tension T increases, so nS increases $$($$↑$$)Also$$ it is given that number of beats per $$sec$$ decreases (i$$.e. x↓$$)Hence$$ nS↑ – nf  $$=$$ x↓        ... $$(i)          →      Wrong            nf  – nS↑ $$=$$ x↓        ... (ii)         →      Correct⇒ nS $$=$$ nf – x $$=$$ $$480$$ – $$10$$ $$=$$ $$470$$ Hz.

A tuning fork of frequency 480 Hz produces 10 beats per second when sounded with a vibrating sonometer string. What must have been the frequency of the string if a slight increase in tension produces lesser beats per second than before

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