A tuning fork A of frequency 200 Hz is sounded with fork B, the number of beats per second is 5. By putting some wax on A, the number of beats increases to 8. The frequency of fork B is
nA – nB = x ... (i) Wrong
nB – nA = x ... (ii) Correct
nB = nA + x = 200 + 5 = 205 Hz.