A tuning fork of frequency n is held near the open end of a tube which is closed at the other end and the length of the tube is adjusted until resonance occurs. If the two shortest lengths that produce resonance are ,l1 and 12, the speed of the sound is

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nl2âl1

nl2âl1/2

2nl2+l1

2nl2âl1

answer is D.

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Detailed Solution

n=v4( l1+x) and n=3v4(l2+x) , here x = end correction . V=4nl1 and 3v=4nl2 or 2v=4nl2âl1 V=2nl2âl1

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