A tuning fork of known frequency $$256$$ Hz makes $$5$$ beats per second with the vibrating string of a piano. The beat frequency decreases to $$2$$ beats per second when the tension in the piano string is slightly increased. The frequency of the piano string before increasing the tension was

Question

Infinity Learn · Accepted Answer

Suppose nP $$=$$ frequency of piano $$=$$ ?  (nP$$∝$$T)nf$$ $$=$$ Frequency of tuning fork $$=$$ $$256$$ Hzx $$=$$ Beat frequency $$=$$ $$5$$ bps, which is decreasing $$(5$$→$$2) after clanging the tension of piano wire Also, tension of piano wire is increasing so nP↓Hence nP↑– nf $$=$$ x↓      →       Wrong           nf – nP↑$$=$$ x↓       →      Correct ⇒ nP $$=$$ nf – x $$=$$ $$256$$ – $$5$$ Hz.

A tuning fork of known frequency 256 Hz makes 5 beats per second with the vibrating string of a piano. The beat frequency decreases to 2 beats per second when the tension in the piano string is slightly increased. The frequency of the piano string before increasing the tension was

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