A tuning fork of known frequency 256 Hz makes 5 beats per second with the vibrating string of a piano. The beat frequency decreases to 2 beats per second when the tension in the piano string is slightly increased. The frequency of the piano string before increasing the tension was
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a
256 + 5 Hz
b
256 + 2Hz
c
256 – 2 Hz
d
256 – 5Hz
answer is D.
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Detailed Solution
Suppose nP = frequency of piano = ? (nP∝T)nf = Frequency of tuning fork = 256 Hzx = Beat frequency = 5 bps, which is decreasing (5→2) after clanging the tension of piano wire Also, tension of piano wire is increasing so nP↓Hence nP↑– nf = x↓ → Wrong nf – nP↑= x↓ → Correct ⇒ nP = nf – x = 256 – 5 Hz.