Download the app

Questions  

A 250 -turn rectangular coil of length 2.1 cm and width 1.25 cm carries a current of 85 μA and subjected to a magnetic field of strength 0.85 T. Work done for rotating the coil by 180° against the torque is

a
4.55μJ
b
2.3μJ
c
1.15μJ
d
9.1μJ

detailed solution

Correct option is D

Work done in a coil W=mBcosθ1-cosθ2When it is rotated by angle 180° thenW=2 m B=2(N I A) B             . . . .(i) Given: N=250,I=85μA=85×10-6 AA=1.25×2.1×10-4 m2≈2.5×10-4 m2B=0.85 TPutting these values in eqn. (i), we get W=2×250×85×10-6×2.5×10-4×0.85≈9.1×10-6 J=9.1μJ

Talk to our academic expert!

+91

Are you a Sri Chaitanya student?


Similar Questions

A circular loop has a radius of 5 cm and it is carrying a current of 0.1 A. Its magnetic moment is


phone icon
whats app icon