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Q.

A 200 -turn solenoid having a length of 5 m and a diameter of 10 cm carries a current of 0.30 A. The magnitude of the magnetic field B→ inside the solenoid is 1.5×10−pT. Find the value of p.

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answer is 5.

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Detailed Solution

The magnetic field at the center of the solenoid is given byB=μ0ni=4π×10−7×200×0.35=1.5×10−5T

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