Turpentine oil is flowing through a tube of length l and radius r. The pressure difference between the two ends of the tube is p; the viscosity of the oil is given by : η=P(r2 - x2)4vl where u is the velocity of oil at a distance x from the axis ofthe tube. From this relation, the dimensions of viscosity η are :

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[M0L0T0]

[MLT-1]

[ML2T-2]

[ML-1T-1]

answer is D.

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Detailed Solution

η=p(r2 - x2)4vl=pr2vl=prv (ML-1 T2 )LT-1=ML-1T-1

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