Twenty seven identical drops of mercury are charged simultaneously to the same potential of 10 units, Assuming the drops are made to combine to form one large drop, then its potential is
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a
45 units
b
135 units
c
270 units
d
90 units
answer is D.
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Detailed Solution
Let r be the radius sf small drop and R, the radius of big drop. Then 43πR3=(27)43πr3 or R=3rCharge on bigger drop = 27 qV=14πεn×27q3r=914πε0×qr=9×10=90 units.