Two adjacent natural frequencies of an organ pipe are formed to be 550 Hz and 650 Hz. Calculate the length of this pipe (in m). (Velocity of sound in air 350 m/s).
In case of open organ pipe we have all types of harmonic, even as well as odd. While in case of close organ pipe we have only odd harmonic.
The ratio of two adjacent frequencies
Hence the adjacent harmonic are 11th and 13th. Both harmonic are odd hence it is the case of close organ pipe. Clearly, the fundamental frequency should be 50 Hz.
The fundamental frequency in case of close organ pipe
Hence length of the pipe
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A tube of certain diameter and of length 48 cm is open at both ends. Its fundamental frequency of resonance is found to be 320 Hz. The velocity of sound in air is 320 m/s. One end of the tube is now closed, considering the effect of end correction, calculate the lowest frequency of resonance for the tube (in Hz).
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