Two alternating voltage generators produce emfs of the same amplitude E0 but with a phase difference of π/3. The resultant emf is

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E0 sinωt+π/3

E0 sinωt+π/6

3E0 sinωt+π/6

3E0 sinωt+π/2

answer is C.

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Detailed Solution

E1=E0sinωt; E2=E0sinωt+π/3E = E2 + E1=E0 sinωt+π/3+E0sinωt=E02sinωt+π/6 cosπ/6=3E0sin ωt+π/6

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