First slide

Gravitaional potential energy

Question

Two artificial satellites A and B of same mass are revolving round the earth at heights h₁ and h₂in circular orbits. If h₂< h₁, the satellite possessing greater K.E. is

Easy

A

A
B

B
C

Both A & B
D

Cannot be determined

Solution

Speed of a satellite moving in circular orbit is given by $\large V=\sqrt{\frac{GM}{r}}$
Where r = Radius of orbit = R + h
$\large \therefore K.E.=\frac12mV^2=\frac{GMm}{2r}=\frac{GMm}{2(R+h)}$
So if ' h ' is less , K.E. will be more.
Hence option - (2) is correct.

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