Q.

Two balls are dropped from the same height at places A and B. The body at B takes two seconds less to reach the ground than the body at A and strikes the ground with a velocity greater than the body at A by 10 m/s. The product of the acceleration due to gravity at the two places A and B is ( in m2s–4)

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a

5

b

25

c

125

d

12.5

answer is B.

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Detailed Solution

For both the bodies, displacement is same. From the given condition2hgA−2hgB=2 .......(1)  and 2gBh−2gAh=10 ......(2)dividing (2) by (1) and then solvinggAgB = 25
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Two balls are dropped from the same height at places A and B. The body at B takes two seconds less to reach the ground than the body at A and strikes the ground with a velocity greater than the body at A by 10 m/s. The product of the acceleration due to gravity at the two places A and B is ( in m2s–4)