Two balls are dropped from the same height at places A and B. The body at B takes two seconds less to reach the ground than the body at A and strikes the ground with a velocity greater than the body at A by 10 m/s. The product of the acceleration due to gravity at the two places A and B is ( in m2s–4)
see full answer
High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET
🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya
a
5
b
25
c
125
d
12.5
answer is B.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
For both the bodies, displacement is same. From the given condition2hgA−2hgB=2 .......(1) and 2gBh−2gAh=10 ......(2)dividing (2) by (1) and then solvinggAgB = 25