Q.

Two balls are thrown simultaneously from ground with same velocity of 10 ms-1 but different angles of projection with horizontal. Both balls fall at same distance 53 m from point of projection. What is the time interval between balls striking the ground?

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a

(3 - 1) s

b

(3 + 1) s

c

3 s

d

1 s

answer is A.

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Detailed Solution

Given, 53=(10)2sin2θg or sin2θ=32∴ 2θ  = 600 or θ  = 300Two different angles of projection are therefore θ and 90° - 0 or 30° and 60°.∴  T1=2usin30°g=1 s∴  T2=2usin60°g=3 s Hence, Δt=T2-T1=(3-1)s
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