Two balls A and B are thrown with speeds u and u/2 respectively. Both the balls cover the same horizontal distance before returning to the plane of projection. If the angle of projection of ball B is 15o with the horizontal, then the angle of projection of A is
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a
sin−1(1/8)
b
12sin−1(1/8)
c
13sin−1(1/8)
d
14sin−1(1/8)
answer is B.
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Detailed Solution
u2sin2θg=(u/2)2sin30∘g=u28g∴ sin2θ=1/8 or 2θ=sin−1(1/8)or θ=12sin−1(1/8)