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Two balls A and B are thrown with speeds u and u/2, respectively. Both the balls cover the same horizontal distance before returning to the plane of projection. If the angle of projection of ball B is 15° with the horizontal, then the angle of projection of A is

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a

sin-118

b

12sin-11-8

c

13sin-118

d

14sin-118

answer is B.

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Detailed Solution

u2sin2θg=(u/2)2sin30°g=u28 g sin2θ=18   or   θ=12sin-118
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